题目内容
【题目】(遂昌县)用递等式计算.
①[1﹣(
+
)]×36
②(
+
)×36
③7.5×4.7+4.7×2.5
④25.3×12﹣33.46÷0.35
⑤
×[
÷(1﹣
)]
⑥
+(
﹣
)÷
.
【答案】①
;②29;③47;④208;⑤4
;⑥![]()
【解析】
试题分析:①④⑤⑥根据四则混合运算的运算顺序计算即可.
②③可据乘法分配律进行计算;
解答:解:①[1﹣(
+
)]×36,
=[1﹣(
+
)]×36,
=[1﹣
]×36,
=
×36,
=
;
②(
+
)×36,
=36×![]()
,
=8+21,
=29;
③7.5×4.7+4.7×2.5,
=4.7×(7.5+2.5),
=4.7×10,
=47;
④25.3×12﹣33.46÷0.35,
=303.6﹣95.6,
=208;
⑤
×[
÷(1﹣
)],
=
×[
÷
],
=
[
],
=
×5,
=4
;
⑥
+(
﹣
)÷
,
=
+(
﹣
)×2,
=
+
×2,
=
+
,
=
.
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