题目内容
(2013?北京模拟)(1)
÷(
+
×5)
(2)
×
-
÷1.25
(3)35.79×37+35.79×82-357.9×1.9
(4)[(0.875-
)×0.25]÷
.
| 3 |
| 4 |
| 3 |
| 10 |
| 1 |
| 5 |
(2)
| 6 |
| 13 |
| 4 |
| 5 |
| 1 |
| 13 |
(3)35.79×37+35.79×82-357.9×1.9
(4)[(0.875-
| 5 |
| 6 |
| 3 |
| 8 |
分析:(1)先算括号内的乘法,再算括号内的加法,最后算括号外的除法;
(2)把小数化为分数,把除法变为乘法,运用乘法分配律简算;
(3)根据数字特点,通过数字转化,运用乘法分配律简算;
(4)把小数化为分数,先算小括号内的,原式变为
×
×
,约分计算.
(2)把小数化为分数,把除法变为乘法,运用乘法分配律简算;
(3)根据数字特点,通过数字转化,运用乘法分配律简算;
(4)把小数化为分数,先算小括号内的,原式变为
| 1 |
| 24 |
| 1 |
| 4 |
| 8 |
| 3 |
解答:解:(1)
÷(
+
×5),
=
÷(
+1),
=
÷
,
=
×
,
=
;
(2)
×
-
÷1.25,
=
×
-
÷
,
=
×
-
×
,
=(
-
)×
,
=
×
,
=
;
(3)35.79×37+35.79×82-357.9×1.9,
=35.79×37+35.79×82-35.79×19,
=35.79×(37+82-19),
=35.79×100,
=3579;
(4)[(0.875-
)×0.25]÷
,
=[(
-
)×
]÷
,
=[
×
]÷
,
=
×
×
,
=
.
| 3 |
| 4 |
| 3 |
| 10 |
| 1 |
| 5 |
=
| 3 |
| 4 |
| 3 |
| 10 |
=
| 3 |
| 4 |
| 13 |
| 10 |
=
| 3 |
| 4 |
| 10 |
| 13 |
=
| 15 |
| 26 |
(2)
| 6 |
| 13 |
| 4 |
| 5 |
| 1 |
| 13 |
=
| 6 |
| 13 |
| 4 |
| 5 |
| 1 |
| 13 |
| 5 |
| 4 |
=
| 6 |
| 13 |
| 4 |
| 5 |
| 1 |
| 13 |
| 4 |
| 5 |
=(
| 6 |
| 13 |
| 1 |
| 13 |
| 4 |
| 5 |
=
| 5 |
| 13 |
| 4 |
| 5 |
=
| 4 |
| 13 |
(3)35.79×37+35.79×82-357.9×1.9,
=35.79×37+35.79×82-35.79×19,
=35.79×(37+82-19),
=35.79×100,
=3579;
(4)[(0.875-
| 5 |
| 6 |
| 3 |
| 8 |
=[(
| 7 |
| 8 |
| 5 |
| 6 |
| 1 |
| 4 |
| 3 |
| 8 |
=[
| 1 |
| 24 |
| 1 |
| 4 |
| 3 |
| 8 |
=
| 1 |
| 24 |
| 1 |
| 4 |
| 8 |
| 3 |
=
| 1 |
| 36 |
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
练习册系列答案
相关题目