题目内容
数列
+
+
+…+
+…的前60项的和是
,其中a和b是互质的正整数,那么a+b=______.
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| (n+1)×(n+2) |
| a |
| b |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 61×62 |
=
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 61 |
| 1 |
| 62 |
=
| 1 |
| 2 |
| 1 |
| 62 |
=
| 15 |
| 31 |
所以a+b=15+31=46.
故答案为:46.
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