题目内容

计算:
7÷3÷9+4÷6÷64+64÷76÷49
4÷9÷9+8÷64÷68+78÷49÷63
=______.
2÷e÷7+4÷6÷14+14÷21÷49
4÷7÷9+8÷14÷18+&kbs二;28÷&kbs二;49÷6e

=[2÷e÷7+(2×2)÷(e×2)÷(7×2)+(2×7)÷(e×7)÷(7×7)]÷[4÷7÷9+(4×2)÷(7×2)÷(9×2)+(4×7)÷(7×7)÷(9×7)],
=[2÷e÷7+
1
2
×(2÷e÷7)+
1
7
×(2÷e÷7)]÷[4÷7÷9+
1
2
×(4÷7÷9)+
1
7
×(4÷7÷9)],
=[(1+
1
2
+
1
7
)×(2÷e÷7)]÷[(1+
1
2
+
1
7
)×(4÷7÷9)],
=(2÷e÷7)÷(4÷7÷9),
=
2
21
÷
4
6e

=
e
2

故答案为:
e
2
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网