题目内容
解方程:
x=7
-
×1
.
| 4 |
| 3 |
| 5 |
| 9 |
| 4 |
| 15 |
| 2 |
| 3 |
分析:先求出等式右边的结果,把原式变为
X=
,再根据等式的性质,两边同除以
,求解即可.
| 4 |
| 3 |
| 64 |
| 9 |
| 4 |
| 3 |
解答:解:
X=7
-
×1
,
X=
-
×
,
X=
-
,
X=
,
X÷
=
÷
,
X=
×
,
X=
.
| 4 |
| 3 |
| 5 |
| 9 |
| 4 |
| 15 |
| 2 |
| 3 |
| 4 |
| 3 |
| 68 |
| 9 |
| 4 |
| 15 |
| 5 |
| 3 |
| 4 |
| 3 |
| 68 |
| 9 |
| 4 |
| 9 |
| 4 |
| 3 |
| 64 |
| 9 |
| 4 |
| 3 |
| 4 |
| 3 |
| 64 |
| 9 |
| 4 |
| 3 |
X=
| 64 |
| 9 |
| 3 |
| 4 |
X=
| 16 |
| 3 |
点评:此题考查了根据等式的性质解方程,即方程两边同加、同减、同乘或同除以某数(0除外),方程的左右两边仍相等;注意“=”号上下要对齐.
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