摘要:数列{an}的前项和为Sn.已知a1=1,an+1=Sn.求证数列{}是等比数列.且Sn+1=4an
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设数列{an}的前项和为Sn,已知a1+2a2+3a3+…+nan=(n-1)Sn+2n(n∈N*).
(1)求a1,a2的值;
(2)求证:数列{Sn+2}是等比数列;
(3)抽去数列{an}中的第1项,第4项,第7项,……,第3n-2项,……,余下的项顺序不变,组成一个新数列{bn},若{bn}的前n项的和为Tn,求证:
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设数列{an}前n项和为Sn,已知a1=a(a≠4),an+1=2Sn+4n(n∈N*)
(Ⅰ)设b n=Sn-4n,求证:数列{bn}是等比数列;
(Ⅱ)求数列{an}的通项公式;
(Ⅲ)若an+1≥an(n∈N*),求实数a取值范围.
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(Ⅰ)设b n=Sn-4n,求证:数列{bn}是等比数列;
(Ⅱ)求数列{an}的通项公式;
(Ⅲ)若an+1≥an(n∈N*),求实数a取值范围.
设数列{an}前n项和为Sn,已知a1=a(a≠4),an+1=2Sn+4n(n∈N*)
(Ⅰ)设b n=Sn-4n,求证:数列{bn}是等比数列;
(Ⅱ)求数列{an}的通项公式;
(Ⅲ)若an+1≥an(n∈N*),求实数a取值范围.
查看习题详情和答案>>
(Ⅰ)设b n=Sn-4n,求证:数列{bn}是等比数列;
(Ⅱ)求数列{an}的通项公式;
(Ⅲ)若an+1≥an(n∈N*),求实数a取值范围.