摘要:解:(1)由a1=S1=1.S2=1+a2.得a2=又3tSn-(2t+3)Sn-1=3t ①3tSn-1-(2t+3)Sn-2=3t ②①-②得3tan-(2t+3)an-1=0

网址:http://m.1010jiajiao.com/timu_id_422747[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网