摘要:②N2(g)+3H2(g) 2NH3(g). ΔH < 0,
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化学反应N2+3H2=2NH3的能量变化如图所示,该反应的热化学方程式是
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A.N2(g)+3H2(g)=2NH3(l);ΔH=2(a-b-c) kJ·mol-1
B.N2(g)+3H2(g)=2NH3(g);ΔH=2(b-a) kJ·mol-1
C.
N2(g)+
H2(g)=NH3(l);ΔH=(b+c-a) kJ·mol-1
D.
N2(g)+
H2((g)=NH3(g);ΔH=(a+b) kJ·mol-1
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