摘要:12. (1)CxHy+(x/2+y/4+m/2)O2mCO2+y/2H2O+ (x-m)CO (2)当m=2时.该烃分子式为C4H8 (3) 烃的分子式 n(CO)/n(CO2) C3H8 1/2 C4H6 1/3 讲析: (1)CxHy+(x/2+y/4+m/2)O2→mCO2+y/2H2O+ (x-m)CO (2)通过Na2O2 mCO2m/2O2.y/2H2Oy/4O2.(x-m)CO (x-m)/2O2 x/2+y/4+1=5 当m=2时 =5/8 解得:x=4 y=8 分子式:C4H8 (3)讨论:固体质量总增重:ΔW=ΔW(CO2) +ΔW(H2O) +ΔW(CO)=28m+y+28(x-m)=28x+y ①根据Na2O2的增重:90≤28x+y≤118 讨论气态烃中:x=3时.6≤y≤8 x=4时y≤6 此条件下合理答案有:C4H6.C4H4.C3H8.C3H6 ②根据燃烧产物通过足量Na2O2产生O2体积为3 mol. =3.因x>m.则x>6-y/2 讨论得气态烃中:x=3时.y>6 x=4时.y>4 根据①②条件需同时满足.从而否定C4H4.C3H6.该烃可能为C3H8.C4H6 再由=3.得y=8时.m=2 =1/2 y=6时.m=3 =1/3

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