摘要：15．化学反应N2+3H2 ＝ 2NH3的能量变化如下图所示.该反应的热化学方程式是( ) A.N2(g)+3H2(g) ＝ 2NH3kJ/mol B.N2(g)+3H2(g) ＝ 2NH3kJ/mol C.N2(g)+H2(g) ＝ NH3kJ/mol D.N2(g)+H2(g) ＝NH3kJ/mol
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化学反应N2＋3H2
2NH3的能量变化如下图所示，该反应的热化学方程式是（ ）
| A．N2(g)＋3H2(g) 2NH3(l) ⊿H ＝2(a—b—c)kJ·mol－1 |
| B．N2(g)＋3H2(g) 2NH3(g) ⊿H ＝2(b—a)kJ·mol－1 |
| C．1/2N2(g)＋3/2H2(g) NH3(l)⊿H ＝ (b＋c—a)kJ·mol－1 |
| D．1/2N2(g)＋3/2H2(g) NH3(g)⊿H ＝ (a＋b)kJ·mol－1 |
化学反应N2＋3H2===2NH3的能量变化如下图所示，该反应的热化学方程式是
[ ]
A．N2(g)＋3H2(g)===2NH3(l) ΔH＝2(a－b－c)kJ/mol
B．N2(g)＋3H2(g)===2NH3(g) ΔH＝2(b－a)kJ/mol
C．1/2N2(g)＋3/2H2(g)===NH3(l) ΔH＝(b＋c－a)kJ/mol
D．1/2N2(g)＋3/2H2(g)===NH3(g) ΔH＝(a＋b)kJ/mol
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B．N2(g)＋3H2(g)===2NH3(g) ΔH＝2(b－a)kJ/mol
C．1/2N2(g)＋3/2H2(g)===NH3(l) ΔH＝(b＋c－a)kJ/mol
D．1/2N2(g)＋3/2H2(g)===NH3(g) ΔH＝(a＋b)kJ/mol
化学反应N2＋3H2===2NH3的能量变化如下图所示，该反应的热化学方程式是
[ ]
A．N2(g)＋3H2(g)===2NH3(l) ΔH＝2(a－b－c)kJ/mol
B．N2(g)＋3H2(g)===2NH3(g) ΔH＝2(b－a)kJ/mol
C．1/2N2(g)＋3/2H2(g)===NH3(l) ΔH＝(b＋c－a)kJ/mol
D．1/2N2(g)＋3/2H2(g)===NH3(g) ΔH＝(a＋b)kJ/mol
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B．N2(g)＋3H2(g)===2NH3(g) ΔH＝2(b－a)kJ/mol
C．1/2N2(g)＋3/2H2(g)===NH3(l) ΔH＝(b＋c－a)kJ/mol
D．1/2N2(g)＋3/2H2(g)===NH3(g) ΔH＝(a＋b)kJ/mol
N2(g)+
H2(g) === NH3(1) △H＝(b+c-a)kJ·mol-1
N2(g)+
H2(g) === NH3(1) △H＝(b+c-a)kJ?mol-1
N2(g)+