摘要:7.已知在1×105Pa.298K条件下.2molH2燃烧生成水蒸气放出484kJ热量.下列热化学方程式正确的是 ( ) A.H2O(g)=H2(g)+1/2O2(g) ΔH=+242kJ·mol-1 B.2H2(g)+O2(g)=2H2O(l) ΔH=-484kJ·mol-1 C.H2(g)+1/2O2(g)=H2O(g) ΔH=+242kJ·mol-1 D.2H2(g)+O2(g)=2H2O(g) ΔH=+484kJ·mol-1
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已知在1×105Pa,298K条件下,2molH2燃烧生成水蒸气放出484kJ热量,下列热化学方程式正确的是
A.H2O(g)=H2(g)+1/2O2(g) ΔH=+242kJ·mol-1
B.2H2(g)+O2(g)=2H2O(l) ΔH=-484kJ·mol-1
C.H2(g)+1/2O2(g)=H2
O(g) ΔH=+242kJ·mol-1
D.2H2(g)+O2(g)=2H2O(g) ΔH=+484kJ·mol-1
查看习题详情和答案>>已知在1.01×105Pa、298K条件下,2molH2燃烧生成水蒸气放出484kJ热量,下列热化学方程式正确的是( )
A.H2O(g)==H2(g) + 1/2O2(g);△H = - 242kJ/mol
B.2H2(g) + O2(g)==2H2O(I);△H = - 484kJ/mol
C.2H2(g) + O2(g)==2H2O(g);△H = + 484kJ/mol
D.H2(g) + 1/2O2(g)==H2O(g);△H = - 242kJ/mol
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已知在1.01×105Pa、298K条件下,2molH2燃烧生成水蒸气时放出484kJ热量.下列热化学方程式中正确的是 | |
| [ ] | |
A. |
H2O(g) |
B. |
2H2(g)+O2(g) |
C. |
H2O(g)+ |
D. |
2H2(g)+O2(g) |