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A.AB=CD,AD=BC,AC=BD
B.ÐA=ÐC,ÐB=ÐD,ÐA=ÐB
C.OA=OC,OB=OD,ÐA=90°
D.ÐA=ÐC,ÐB+ÐC=180°,ÐAOB=ÐBOC
四边形ABCD的对角线AC、BD相交于点O,下列各组条件中,不能判定四边形ABCD是矩形的为
B.AO=CO,BO=DO,∠A=90°
C.∠BAD=∠BCD,∠ABC+∠BCD=180°,∠AOB=∠BOC
D.∠BAD=∠BCD,∠ABC=∠ADC,∠BAD=∠ABC