摘要:A.已知2H2(g)+O2(g) 2H2O(g),△H=-483.6kJ/mol.则氢气的燃烧热为241.8kJ/molB.由单质A转化为单质B是一个吸热过程.由此可知单质B比单质A稳定
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已知2H2(g)+O2(g)=2H2O(g)△H=-484KJ/moL,则反应H2O(g)=H2(g)+
O2(g) 的△H为( )
A.-484kJ/mol
B.+484kJ/mol
C.-242kJ/mol
D.+242kJ/mol
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A.-484kJ/mol
B.+484kJ/mol
C.-242kJ/mol
D.+242kJ/mol
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