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设f(x)是以2为周期的奇函数,且f(－)=3,若sinα=,则f(4cos2α)= ( )
A．－3 B．3 C．－ D．
)=3,若sinα=
,则f(4cos2α)= (
)
)=3,若sinα=
,则f(4cos2α)= (
)
)=3,若sinα=
,则f(4cos2α)= ( )
)=3,若sinα=
,则f(4cos2α)= ( )
)=3,若sinα=
,则f(4cos2α)= ( )