摘要:19.解:(Ⅰ)连接A1B.设A1B∩AB1=E.连结DE.∵ABC―A1B1C是正三棱柱且AA1=AB.∴四边形A1ABB1是正方形.∴E是A1B的中点. 又D是BC的中点.∴DE//A1C

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