摘要:23.如图9.在平面直角坐标系中.以点为圆心.2为半径作圆.交轴于两点.开口向下的抛物线经过点.且其顶点在上. (1)求的大小, (2)写出两点的坐标, (3)试确定此抛物线的解析式, (4)在该抛物线上是否存在一点.使线段与互相平分?若存在.求出点的坐标,若不存在.请说明理由. (08新疆乌鲁木齐23题解答)23.解:(1)作轴.为垂足. .半径······················································ 1分 .······································ 3分 (2).半径 .故.············································ 5分 ········································································· 6分 (3)由圆与抛物线的对称性可知抛物线的顶点的坐标为··································· 7分 设抛物线解析式·················································································· 8分 把点代入上式.解得······································································· 9分 ····································································································· 10分 (4)假设存在点使线段与互相平分.则四边形是平行四边形········· 11分 且. 轴.点在轴上.·············································································· 12分 又..即. 又满足. 点在抛物线上······································································································ 13分 所以存在使线段与互相平分.···························································· 14分
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如图,在平面直角坐标系中,一底角为60°的等腰梯形ABCD的下底AB在x轴的正半轴上,A为坐标原点,点B的坐标为(m,0),对角线BD平分∠ABC,一动点P在BD上以每秒一个单位长度的速度由B→D运动(点P不与B,D重合).过P作PE⊥BD交AB于
点E,交线段BC(或CD)于点F.
(1)用含m的代数式表示线段AD的长是 ;
(2)当直线PE经过点C时,它的解析式为y=
x-2
,求m的值;
(3)在上述结论下,设动点P运动了t秒时,△AEF的面积为S,求S与t的函数关系式;并写出t为何值时,S取得最大值,最大值是多少? 查看习题详情和答案>>
(1)用含m的代数式表示线段AD的长是
(2)当直线PE经过点C时,它的解析式为y=
| 3 |
| 3 |
(3)在上述结论下,设动点P运动了t秒时,△AEF的面积为S,求S与t的函数关系式;并写出t为何值时,S取得最大值,最大值是多少? 查看习题详情和答案>>
如图,在平面直角坐标系中,以点M(0,
)为圆心,以2
长为半径作⊙M交x轴
于A,B两点,交y轴于C,D两点,连接AM并延长交⊙M于P点,连接PC交x轴于E.
(1)求出CP所在直线的解析式;
(2)连接AC,请求△ACP的面积. 查看习题详情和答案>>
| 3 |
| 3 |
(1)求出CP所在直线的解析式;
(2)连接AC,请求△ACP的面积. 查看习题详情和答案>>
如图,在平面直角坐标系中,A(2
,0),B(2
,2).把矩形OABC逆时针旋转30°得到矩形OA1B1C1,
(1)求B1点的坐标;
(2)求过点(2,0)且平分矩形OA1B1C1面积的直线l方程;
(3)设(2)中直线l交y轴于点P,直接写出△PC1O与△PB1A1的面积和的值及△POA1与△PB1C1的面积差的值.
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| 3 |
| 3 |
(1)求B1点的坐标;
(2)求过点(2,0)且平分矩形OA1B1C1面积的直线l方程;
(3)设(2)中直线l交y轴于点P,直接写出△PC1O与△PB1A1的面积和的值及△POA1与△PB1C1的面积差的值.