(1)95 ＝ 4.8g×5% ＝0.24g CH3COOH + NaOH ＝ CH3COONa + H2O 60 40 m(CH3COOH) 0.24g ——青夏教育精英家教网—

摘要：(1)95 ＝ 4.8g×5% ＝0.24g CH3COOH + NaOH ＝ CH3COONa + H2O 60 40 m(CH3COOH) 0.24g == m(CH3COOH) ＝0.36g 则100mL样品中含CH3COOH:0.36g ×10 = 3.6g 所以该食醋合格

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解：（1）95 (2分)

（2）m（NaOH）＝ 4.8g×5% ＝0.24g (1分)

CH3COOH + NaOH ＝ CH3COONa + H2O

60 40

m(CH3COOH) 0.24g

m(CH3COOH) ＝ 0.24g× ＝ 0.36g （1分）

则100mL样品中含CH3COOH：0.36g × = 3.6g

合格

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