ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬ÑØxÖáÕý·½Ïò´«²¥µÄÒ»ÁкᲨÔÚijʱ¿ÌµÄ²¨ÐÎͼΪһÕýÏÒÇúÏߣ¬Æä²¨ËÙΪ200m/s£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®´Óͼʾʱ¿Ì¿ªÊ¼£¬Öʵãb±ÈÖʵãaÏȵ½Æ½ºâλÖÃ
B£®´Óͼʾʱ¿Ì¿ªÊ¼£¬¾­0.01sÖʵãaͨ¹ýµÄ·³ÌΪ0.1m
C£®Èô¸Ã²¨´«²¥ÖÐÓöµ½¿íÔ¼3mµÄÕϰ­ÎïÄÜ·¢ÉúÃ÷ÏÔµÄÑÜÉäÏÖÏó
D£®Èô¸Ã²¨²¨Ô´´ÓOµãÑØxÖáÕýÏòÔ˶¯£¬ÔòÔÚx=2000m´¦½ÓÊÕµ½µÄ²¨µÄƵÂÊСÓÚ50Hz
¾«Ó¢¼Ò½ÌÍø
A¡¢²¨ÑØxÖáÕý·½Ïò´«²¥£¬´ËʱbÖʵãÕñ¶¯·½ÏòÏòÏ£¬¶øaÖʵãÖ±½ÓÏòÏÂÏòƽºâλÖÃÔ˶¯£¬ÔòÖʵãa±ÈÖʵãbÏȵ½Æ½ºâλÖ㮹ÊA´íÎó£®
    B¡¢ÓÉͼ¦Ë=4m£¬ÔòT=
¦Ë
v
=0.02s
      t=0.01s=
1
2
T
£¬¾­0.01sÖʵãaͨ¹ýµÄ·³ÌΪS=2A=0.1m£®¹ÊBÕýÈ·£®
    C¡¢¦Ë=4m£¾3m£¬ÄÜ·¢ÉúÃ÷ÏÔµÄÑÜÉäÏÖÏó£®¹ÊCÕýÈ·£®
    D¡¢Èô¸Ã²¨²¨Ô´´ÓOµãÑØxÖáÕýÏòÔ˶¯£¬ÔòÔÚx=2000m´¦½ÓÊÕµ½µÄ²¨µÄƵÂÊÉý¸ß£¬´óÓÚ50Hz£®¹ÊD´íÎó£®
¹ÊÑ¡C
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø