ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÓÐÁ½Áмòгºá²¨µÄÕñ·ù¶¼ÊÇ10cm£¬´«²¥ËÙ¶È´óСÏàͬ¡£OµãÊÇʵÏß²¨µÄ²¨Ô´£¬ÊµÏß²¨ÑØ
ÖáÕý·½Ïò´«²¥£¬²¨µÄƵÂÊΪ5Hz£»ÐéÏß²¨ÑØ
ÖḺ·½Ïò´«²¥¡£Ä³Ê±¿ÌʵÏß²¨¸ÕºÃ´«µ½
=12m´¦Öʵ㣬ÐéÏß²¨¸ÕºÃ´«µ½
=0´¦Öʵ㣬ÈçͼËùʾ£¬ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
![]()
A.ʵÏß²¨ºÍÐéÏß²¨µÄÖÜÆÚÖ®±ÈΪ3£º2
B.ƽºâλÖÃΪ
=6m´¦µÄÖʵã´Ë¿ÌÕñ¶¯ËÙ¶ÈΪ0
C.ƽºâλÖÃΪ
=6m´¦µÄÖʵãʼÖÕ´¦ÓÚÕñ¶¯¼ÓÇ¿Çø£¬Õñ·ùΪ20cm
D.´Óͼʾʱ¿ÌÆðÔÙ¾¹ý0.5s£¬
=5m´¦µÄÖʵãµÄÎ»ÒÆy<0
¡¾´ð°¸¡¿D
¡¾½âÎö¡¿
A£®ÓÉͼ֪²¨³¤
£¬![]()
ÓÉ
µÃ
![]()
²¨ËÙ
Ïàͬ£¬ÔòÓÐ
![]()
¹ÊA´íÎó£»
B£®¶ÔÓÚʵÏß²¨£¬ÓÉͼ֪´Ëʱ
´¦µÄÖʵãλÓÚÆ½ºâλÖã¬ÏòÉÏÕñ¶¯ÆäÕñ¶¯ËÙ¶È×î´ó£¬¶ÔÓÚÐéÏß²¨£¬ÓÉͼ֪´Ëʱ
´¦µÄÖʵãλÓÚÆ½ºâλÖã¬ÏòÉÏÕñ¶¯ÆäÕñ¶¯ËÙ¶È×î´ó£¬¸ù¾Ýµþ¼ÓÔÀí¿ÉµÃ´Ëʱ
´¦µÄÖʵã´Ë¿ÌÕñ¶¯ËÙ¶È×î´ó£¬¹ÊB´íÎó£»
C£®Á½Áв¨ÆµÂʲ»Í¬£¬²»ÄÜÐγÉÎȶ¨µÄ¸ÉÉæÏÖÏ󣬲»´æÔÚÖʵãʼÖÕ´¦ÓÚÕñ¶¯¼ÓÇ¿Çø£¬¹ÊC´íÎó£»
D£®¸ù¾Ý
¿ÉµÃ
![]()
Ôò0.5sÏ൱ÓÚ
¸öÖÜÆÚ£¬¶ÔÓÚʵÏß²¨£¬
ʱ
ÖʵãλÓÚ²¨·å£¬Ôò´Óͼʾʱ¿ÌÆðÔÙ¾¹ý
¸öÖÜÆÚʱÖʵãλÓÚ²¨¹È£¬ÔòÓÐ
![]()
ÓÉÓÚ
£¬ÔòÓÐ
![]()
0.5sÏ൱ÓÚ
¸öÖÜÆÚ£¬¶ÔÓÚÐéÏß²¨£¬
ʱ
µÄÖʵãÎ»ÒÆÎª¸ºÇÒÏòÉÏÔ˶¯£¬Ôò´Óͼʾʱ¿ÌÆðÔÙ¾¹ý
¸öÖÜÆÚÊ±Î»ÒÆ
![]()
¹Ê×îÖÕ
![]()
¹ÊDÕýÈ·¡£
¹ÊÑ¡D¡£