ÌâÄ¿ÄÚÈÝ

ÖÊÁ¿Îªm=1kgµÄСÎï¿éÇáÇá·ÅÔÚˮƽÔÈËÙÔ˶¯µÄ´«ËÍ´øÉϵÄPµã£¬Ëæ´«ËÍ´øÔ˶¯µ½AµãºóˮƽÅ׳ö£¬Ð¡Îï¿éÇ¡ºÃÎÞÅöײµÄÑØÔ²»¡ÇÐÏß´ÓBµã½øÈëÊúÖ±¹â»¬Ô²¹Â¹ìµÀÏ»¬¡£B¡¢CΪԲ»¡µÄÁ½¶Ëµã£¬ÆäÁ¬Ïßˮƽ¡£ÒÑÖªÔ²»¡°ë¾¶R=1.0mÔ²»¡¶ÔÓ¦Ô²ÐĽǣ¬¹ìµÀ×îµÍµãΪO£¬Aµã¾àË®Æ½ÃæµÄ¸ß¶Èh=0.8m¡£Ð¡Îï¿éÀ뿪CµãºóÇ¡ÄÜÎÞÅöײµÄÑØ¹Ì¶¨Ð±ÃæÏòÉÏÔ˶¯£¬0.8sºó¾­¹ýDµã£¬Îï¿éÓëÐ±Ãæ¼äµÄ»¬¶¯Ä¦²ÁÒòÊýΪ=0.33£¨g=10m/s2,sin37¡ã=0.6,cos37¡ã=0.8£©ÊÔÇó£º
   £¨1£©Ð¡Îï¿éÀ뿪AµãµÄˮƽ³õËÙ¶Èv1
   £¨2£©Ð¡Îï¿é¾­¹ýOµãʱ¶Ô¹ìµÀµÄѹÁ¦
   £¨3£©Ð±ÃæÉÏCD¼äµÄ¾àÀë

   £¨4£©¼ÙÉèСÎï¿éÓë´«ËÍ´ø¼äµÄ¶¯Ä¦²ÁÒòÊýΪ 0 .3£¬´«ËÍ´øµÄËÙ¶ÈΪ5m/s£¬ÔòPA¼äµÄ¾àÀëÊǶàÉÙ£¿


½â£º£¨1£©¶ÔСÎï¿é£¬ÓÉAµ½BÓÐ ÔÚBµã ËùÒÔ £¨2£©¶ÔСÎï¿é£¬ÓÉBµ½OÓÐ ÆäÖÐ ÔÚOµã ËùÒÔN=43NÓÉÅ£¶ÙµÚÈý¶¨ÂÉÖª¶Ô¹ìµÀµÄѹÁ¦Îª £¨3£©Îï¿éÑØÐ±ÃæÉÏ»¬£º ËùÒÔÎï¿éÑØÐ±ÃæÉÏ»¬£º ÓÉ»úеÄÜÊØºã֪СÎï¿éÓÉCÉÏÉýµ½×î¸ßµãÀúʱ СÎï¿éÓÉ×î¸ßµã»Øµ½DµãÀúʱ ¹Ê ¼´ £¨4£©Ð¡Îï¿éÔÚ´«ËÍ´øÉϼÓËÙ¹ý³Ì£º PA¼äµÄ¾àÀëÊÇ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø