ÌâÄ¿ÄÚÈÝ
Ò»×ã¹»¸ßµÄÄڱڹ⻬µÄµ¼ÈÈÆø¸×ÊúÖ±µØ½þ·ÅÔÚÊ¢ÓбùË®»ìºÏÎïµÄË®²ÛÖУ¬Óò»¼ÆÖÊÁ¿µÄ»îÈû·â±ÕÁËÒ»¶¨ÖÊÁ¿µÄÀíÏëÆøÌ壬ÈçͼËùʾ¡£¿ªÊ¼Ê±ÆøÌåµÄÌå»ýΪ2.0¡Á10-3m3£¬ÏÖ»ºÂýµØÔÚ»îÈûÉϵ¹ÉÏÒ»¶¨Á¿µÄϸɳ£¬×îºó»îÈû¾²Ö¹Ê±ÆøÌåµÄÌå»ýÇ¡ºÃ±äΪÔÀ´µÄÒ»°ë£¬È»ºó½«Æø¸×ÒÆ³öË®²Û£¬»ºÂý¼ÓÈÈ£¬Ê¹ÆøÌåζȱäΪ137ºC¡££¨´óÆøÑ¹Ç¿Îª1.0¡Á105Pa£©
£¨1£©ÇóÆø¸×ÄÚÆøÌå×îÖÕµÄÌå»ý£»
£¨2£©ÔÚp-VͼÉÏ»³öÕû¸ö¹ý³ÌÖÐÆø¸×ÄÚÆøÌåµÄ״̬±ä»¯£¨ÇëÓüýÍ·ÔÚͼÏßÉϱê³ö״̬±ä»¯µÄ·½Ïò£©¡£
¡¾´ð°¸¡¿
½â£º£¨1£©p1=1.0¡Á105Pa£¬V1=2.0¡Á10-3m3£¬T1 = 273K
p2= =2.0¡Á105Pa£¬ £¨3·Ö£©
V2=1.0¡Á10-3m3£¬T2 = 273K
p3=2.0¡Á105Pa£¬ V3=?£¬T3 = 410K
V2= = m3= 1.5¡Á10-3m3£¨3·Ö£©
£¨2£©Èçͼ£¨4·Ö£©
![]()
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿