ÌâÄ¿ÄÚÈÝ

 Ò»×ã¹»¸ßµÄÄڱڹ⻬µÄµ¼ÈÈÆø¸×ÊúÖ±µØ½þ·ÅÔÚÊ¢ÓбùË®»ìºÏÎïµÄË®²ÛÖУ¬Óò»¼ÆÖÊÁ¿µÄ»îÈû·â±ÕÁËÒ»¶¨ÖÊÁ¿µÄÀíÏëÆøÌ壬ÈçͼËùʾ¡£¿ªÊ¼Ê±ÆøÌåµÄÌå»ýΪ2.0¡Á10-3m3£¬ÏÖ»ºÂýµØÔÚ»îÈûÉϵ¹ÉÏÒ»¶¨Á¿µÄϸɳ£¬×îºó»îÈû¾²Ö¹Ê±ÆøÌåµÄÌå»ýÇ¡ºÃ±äΪԭÀ´µÄÒ»°ë£¬È»ºó½«Æø¸×ÒÆ³öË®²Û£¬»ºÂý¼ÓÈÈ£¬Ê¹ÆøÌåζȱäΪ137ºC¡££¨´óÆøÑ¹Ç¿Îª1.0¡Á105Pa£©

£¨1£©ÇóÆø¸×ÄÚÆøÌå×îÖÕµÄÌå»ý£»

£¨2£©ÔÚp-VͼÉÏ»­³öÕû¸ö¹ý³ÌÖÐÆø¸×ÄÚÆøÌåµÄ״̬±ä»¯£¨ÇëÓüýÍ·ÔÚͼÏßÉϱê³ö״̬±ä»¯µÄ·½Ïò£©¡£

 

 

 

 

 

 

 

 

¡¾´ð°¸¡¿

 ½â£º£¨1£©p1=1.0¡Á105Pa£¬V1=2.0¡Á10-3m3£¬T1 = 273K

p2= =2.0¡Á105Pa£¬   £¨3·Ö£©

V2=1.0¡Á10-3m3£¬T2 = 273K  

p3=2.0¡Á105Pa£¬       V3=?£¬T3 = 410K

V2= =  m3= 1.5¡Á10-3m3£¨3·Ö£©

£¨2£©Èçͼ£¨4·Ö£©

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø