ÌâÄ¿ÄÚÈÝ

ºþÃæÉÏÒ»µãOÉÏÏÂÕñ¶¯£¬Õñ·ùΪ0.2 m£¬ÒÔOµãΪԲÐÄÐγÉÔ²ÐÎË®²¨£¬ÈçͼËùʾ£¬A¡¢B¡¢OÈýµãÔÚÒ»ÌõÖ±ÏßÉÏ£¬OA¼ä¾àÀëΪ4.0 m£¬OB¼ä¾àÀëΪ2.4 m£»Ä³Ê±¿ÌOµã´¦ÔÚ²¨·åλÖ㬹۲췢ÏÖ2 sºó´Ë²¨·å´«µ½Aµã£¬´ËʱOµãÕýͨ¹ýƽºâλÖÃÏòÏÂÔ˶¯£¬OA¼ä»¹ÓÐÒ»¸ö²¨·å£»½«Ë®²¨½üËÆÎª¼òг²¨¡£
£¨1£©Çó´ËË®²¨µÄ´«²¥ËÙ¶È¡¢ÖÜÆÚºÍ²¨³¤£»
£¨2£©ÒÔOµã´¦ÔÚ²¨·åλÖÃΪ0ʱ¿Ì£¬Ä³Í¬Ñ§´òËã¸ù¾ÝOB¼ä¾àÀëÓ벨³¤µÄ¹ØÏµÈ·¶¨BµãÔÚ0ʱ¿ÌµÄÕñ¶¯Çé¿ö£¬»­³öBµãµÄÕñ¶¯Í¼Ïó¡£ÄãÈÏΪ¸ÃͬѧµÄ˼·ÊÇ·ñ¿ÉÐУ¿Èô¿ÉÐУ¬»­³öBµãÕñ¶¯Í¼Ïó£»Èô²»¿ÉÐУ¬Çë¸ø³öÕýȷ˼·²¢»­³öBµãµÄÕñ¶¯Í¼Ïó¡£
½â£º£¨1£©v==2 m/s???
¦¤t=T£¬T=1.6 s
¦Ë=vT=3.2 m
£¨2£©¿ÉÐУ¬Õñ¶¯Í¼ÏóÈçͼËùʾ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø