ÌâÄ¿ÄÚÈÝ
¡°ÑéÖ¤»úеÄÜÊØºã¶¨ÂÉ¡±µÄʵÑéÖУ®Í¼(¼×)ÊÇ´òµã¼ÆÊ±Æ÷´ò³öµÄÒ»ÌõÖ½´ø£¬Ñ¡È¡ÆäÖÐÁ¬ÐøµÄ¼ÆÊ±µã±êΪA¡¢B¡¢C¡¡G¡¢H¡¢I£¬¶ÔBH¶Î½øÐÐÑо¿£®
¢ÙÒÑÖª´òµã¼ÆÊ±Æ÷µçԴƵÂÊΪ50Hz£¬ÔòÖ½´øÉÏ´òÏàÁÚÁ½µãµÄʱ¼ä¼ä¸ôΪ_______£®
¢ÚÓÿ̶ȳ߲âÁ¿¾àÀëʱÈçͼ(ÒÒ)£¬¶Á³öA¡¢CÁ½µã¼ä¾àΪ_________ cm£¬Bµã¶ÔÓ¦µÄËÙ¶ÈvB£½_________m/s£¨±£ÁôÈýλÓÐЧÊý×Ö£©£»
¢ÛÈôHµã¶ÔÓ¦µÄËÙ¶ÈΪvH£¬ÖØÎïÏÂÂäµÄ¸ß¶ÈΪhBH£¬µ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£¬ÎªÍê³ÉʵÑ飬Ҫ±È½Ï
Óë_________________´óС£¨ÓÃ×Öĸ±íʾ£©£®

¢ÙÒÑÖª´òµã¼ÆÊ±Æ÷µçԴƵÂÊΪ50Hz£¬ÔòÖ½´øÉÏ´òÏàÁÚÁ½µãµÄʱ¼ä¼ä¸ôΪ_______£®
¢ÚÓÿ̶ȳ߲âÁ¿¾àÀëʱÈçͼ(ÒÒ)£¬¶Á³öA¡¢CÁ½µã¼ä¾àΪ_________ cm£¬Bµã¶ÔÓ¦µÄËÙ¶ÈvB£½_________m/s£¨±£ÁôÈýλÓÐЧÊý×Ö£©£»
¢ÛÈôHµã¶ÔÓ¦µÄËÙ¶ÈΪvH£¬ÖØÎïÏÂÂäµÄ¸ß¶ÈΪhBH£¬µ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£¬ÎªÍê³ÉʵÑ飬Ҫ±È½Ï
(1)¢Ù0.02s£¨2·Ö£¬ÊýÖµºÍµ¥Î»¸÷1·Ö£¬¿É¿ÆÑ§¼ÆÊý·¨±íʾ£©
¢Ú5.40(2·Ö£¬5.33~5.43¾ù¿É)£» 1.35(2·Ö£¬1.33~1.36¾ù¿É) ¢Û
vH2£ghBH (2·Ö)£»
¢Ú5.40(2·Ö£¬5.33~5.43¾ù¿É)£» 1.35(2·Ö£¬1.33~1.36¾ù¿É) ¢Û
ÊÔÌâ·ÖÎö£º¢Ù´òµã¼ÆÊ±Æ÷µçԴƵÂÊΪ50Hz£¬Ôòÿ¸ô0.02s´òÒ»µã¡£¢Ú SAC=(5.90-0.50)cm=5.40cm£¬
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿