题目内容
化简:cos(25°+x)cos(20°-x)-cos(65°-x)sin(20°-x)=______.
cos(25°+x)cos(20°-x)-cos(65°-x)sin(20°-x)
=cos(25°+x)cos(20°-x)-cos[90°-(25°+x)]sin(20°-x)
=cos(25°+x)cos(20°-x)-sin(25°+x)sin(20°-x)
=cos[(25°+x)+(20°-x)]
=cos45°
=
.
故答案为:
=cos(25°+x)cos(20°-x)-cos[90°-(25°+x)]sin(20°-x)
=cos(25°+x)cos(20°-x)-sin(25°+x)sin(20°-x)
=cos[(25°+x)+(20°-x)]
=cos45°
=
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故答案为:
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