题目内容
计算题:
(1)2log3
+log312-(0.7)0+0.25-1;
(2)(lg5)2+lg2×lg50.
(1)2log3
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| 2 |
(2)(lg5)2+lg2×lg50.
(1)2log3
+log312-(0.7)0+0.25-1=-2log32+1+2log32-1+4=4.
(2)(lg5)2+lg2×lg50=(lg5)2+lg2(lg5+1)=lg5(lg5+lg2)+lg2=lg5+lg2=1.
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| 2 |
(2)(lg5)2+lg2×lg50=(lg5)2+lg2(lg5+1)=lg5(lg5+lg2)+lg2=lg5+lg2=1.
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