题目内容
设O、A、B、C为平面上四个点,
=
,
=
,
=
,且
+
+
=
,
•
=
•
=
•
=-1,则|
|+|
|+|
|等于( )
| OA |
| a |
| OB |
| b |
| OC |
| c |
| a |
| b |
| c |
| 0 |
| a |
| b |
| b |
| c |
| c |
| a |
| a |
| b |
| c |
A.2
| B.2
| C.3
| D.3
|
∵
+
+
=
,
•
=
•
=
•
=-1,∴
2+
2+
2-6=0,
把
+
=-
两边平方得 a2+
2-2=
2,∴
2=2,∴|
|=
,a2+
2=4,
把
+
=-
两边平方得 a2+
2-2=
2,∴a2+2-2=
2,∴a2=
2=2,
∴|
|=|
|=
,则|
|+|
|+|
|=3
,
故选 C.
| a |
| b |
| c |
| 0 |
| a |
| b |
| b |
| c |
| c |
| a |
| a |
| b |
| c |
把
| a |
| b |
| c |
| b |
| c |
| c |
| c |
| 2 |
| b |
把
| a |
| c |
| b |
| c |
| b |
| b |
| b |
∴|
| a |
| b |
| 2 |
| a |
| b |
| c |
| 2 |
故选 C.
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