Question

圆心在原点且与直线x+y-

2

=0相切的圆方程为______．

Answer 1

设所求的圆的方程为：x²+y²=r²
∵直线 x+y-

2

=0与圆相切
圆心（0，0）到直线x+y-

2

=0的距离d=

2

2

=1=r
所求的圆的方程为：x²+y²=1
故答案为：x²+y²=1