题目内容
已知
=(1,2,-1),
=(-2,3,0),若(n
+
)∥(
-
),则实数n=______.
| a |
| b |
| a |
| b |
| a |
| b |
∵
=(1,2,-1),
=(-2,3,0),
∴n
+
=n(1,2,-1)+(-2,3,0)=(n-2,2n+3,-n)
-
=(1,2,-1)-(-2,3,0)=(3,-1,-1)
∵(n
+
)∥(
-
),∴
=
=
,
解得,n=-1
故答案为-1
| a |
| b |
∴n
| a |
| b |
| a |
| b |
∵(n
| a |
| b |
| a |
| b |
| n-2 |
| 3 |
| 2n+3 |
| -1 |
| -n |
| -1 |
解得,n=-1
故答案为-1
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