题目内容
已知||
|=1,|
|=2.
(Ⅰ)若
∥
,求
•
;
(Ⅱ)若
、
的夹角为60°,求|
+
|;
(Ⅲ)若
-
与
垂直,求当k为何值时,(k
-
)⊥(
+2
)?
| a |
| b |
(Ⅰ)若
| a |
| b |
| a |
| b |
(Ⅱ)若
| a |
| b |
| a |
| b |
(Ⅲ)若
| a |
| b |
| a |
| a |
| b |
| a |
| b |
(Ⅰ)
•
=±|
|•|
|=±2(5分)
(Ⅱ)
•
=|
|•|
|cos60°=1|
+
|2=|
|2+
•
+|
|2=6,
∴|
+
|=
(10分)
(Ⅲ) 若
-
与
垂直
∴(
-
)•
=0
∴
•
=|
|2=1
使得(k
-
)⊥(
+2
),只要(k
-
)•(
+2
)=0(12分)
即k|
|2+(2k-1)
•
-2|
|2=0(14分)
∴k=3(15分)
| a |
| b |
| a |
| b |
(Ⅱ)
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| a |
| b |
| b |
∴|
| a |
| b |
| 6 |
(Ⅲ) 若
| a |
| b |
| a |
∴(
| a |
| b |
| a |
∴
| a |
| b |
| a |
使得(k
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| b |
即k|
| a |
| a |
| b |
| b |
∴k=3(15分)
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