题目内容
已知向量
=(1,2),
=(2,-3).若向量
满足(
+
)∥
,
⊥(
+
),则
=( )
| a |
| b |
| c |
| c |
| a |
| b |
| c |
| a |
| b |
| c |
A.(
| B.(-
| C.(
| D.(-
|
设
=(x,y),则
+
=(x+1,y+2),
+
=(3,-1).
∵(
+
)∥
,
⊥(
+
),
∴2(y+2)=-3(x+1),3x-y=0.
∴x=-
,y=-
,
故选D
| c |
| c |
| a |
| a |
| b |
∵(
| c |
| a |
| b |
| c |
| a |
| b |
∴2(y+2)=-3(x+1),3x-y=0.
∴x=-
| 7 |
| 9 |
| 7 |
| 3 |
故选D
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