题目内容
某毕业生参加人才招聘会,分别向甲、乙、丙三个公司投递了个人简历,假定该毕业生得到甲公司面试的概率为
,得到乙、丙公司面试的概率均为P,且三个公司是否让其面试是相互独立的.记X为该毕业生得到面试的公司个数.若P(X=0)=
,则随机变量X的数学期望E(X)=______.
| 2 |
| 3 |
| 1 |
| 12 |
由题意知X为该毕业生得到面试的公司个数,则X的可能取值是0,1,2,3,
∵P(X=0)=
,
∴
(1-p)2 =
,
∴p=
,
p(x=1)=
×
×
+
×
×
+
×
×
=
P(X=2)=
×
×
+
×
×
+
×
×
=
,
p(x=3)=1-
-
-
=
,
∴EX=1×
+2×
+3×
=
,
故答案为:
∵P(X=0)=
| 1 |
| 12 |
∴
| 1 |
| 3 |
| 1 |
| 12 |
∴p=
| 1 |
| 2 |
p(x=1)=
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 4 |
| 12 |
P(X=2)=
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 5 |
| 12 |
p(x=3)=1-
| 1 |
| 12 |
| 4 |
| 12 |
| 5 |
| 12 |
| 2 |
| 12 |
∴EX=1×
| 4 |
| 12 |
| 5 |
| 12 |
| 2 |
| 12 |
| 5 |
| 3 |
故答案为:
| 5 |
| 3 |
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