Question

已知集合A={x|x²-2x-3≤0},B={x|x²+px+q＜0},若A∩B={x|-1≤x＜2},则p、q满足……(    )

A.2p+q+4=0                             B.p+q+5=0

C.p+q=0                                   D.p-q=0

Answer 1

A

解析：A={x|-1≤x≤3},又A∩B={x|-1≤x＜2},可知方程x²+px+q=0必有一根为2.