Question

直线b²x－a²y－a²b²=0(a·b≠0)在y轴上的截距为

A.|b|                                                                B.b²

C.－b²                                                              D.±b

Answer 1

解析：将原方程整理成截距式得＋=1,知在y轴上的截距为－b².

答案：C