题目内容

(本题满分15分) 设函数,若在点处的切线斜率为

(Ⅰ)用表示

(Ⅱ)设,若对定义域内的恒成立,

(ⅰ)求实数的取值范围;

(ⅱ)对任意的,证明:

 

【答案】

(Ⅰ)

(Ⅱ)(ⅰ)  (ⅱ)见解析

【解析】解:(Ⅰ),依题意有:;  ……2′

(Ⅱ)恒成立.

   (ⅰ)恒成立即.  

 恒成立,则.

    当时,

    ,则,g’(x)>0,g(x)单调递增,当,g’(x)<0,g(x) 单调递减,则,符合题意;

恒成立,实数a的取值范围为

;                             ……6′

(ⅱ)由(ⅰ)知,恒成立,实数a的取值范围为.

方法一:令,考虑函数

则对任意的,成立.                 ……7′

思路分析:第一问中利用,依题意有:

第二问,恒成立.

   (ⅰ)恒成立即.恒成立,则.

时,

(ⅱ)由(ⅰ)知,恒成立,实数a的取值范围为.

方法一:令,考虑函数

 

练习册系列答案
相关题目

((本题满分15分)
某有奖销售将商品的售价提高120元后允许顾客有3次抽奖的机会,每次抽奖的方法是在已经设置并打开了程序的电脑上按“Enter”键,电脑将随机产生一个                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        1~6的整数数作为号码,若该号码是3的倍数则顾客获奖,每次中奖的奖金为100元,运用所学的知识说明这样的活动对商家是否有利。

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网