题目内容
sin
+cos
+tan(-
)+sin(-
)•cos(-
)=
| 25π |
| 6 |
| 10π |
| 3 |
| 25π |
| 4 |
| 7π |
| 3 |
| 13π |
| 6 |
-
| 7 |
| 4 |
-
.| 7 |
| 4 |
分析:利用诱导公式把要求的式子化为,sin
+cos
+tan(-
)+sin(-
)cos(-
),即 sin
-cos
-tan(
)-sin(
)cos(
),运算求得结果.
| π |
| 6 |
| 4π |
| 3 |
| π |
| 4 |
| π |
| 3 |
| π |
| 6 |
| π |
| 6 |
| π |
| 3 |
| π |
| 4 |
| π |
| 3 |
| π |
| 6 |
解答:解:sin
+cos
+tan(-
)+sin(-
)•cos(-
)=sin
+cos
+tan(-
)+sin(-
)cos(-
)
=sin
-cos
-tan(
)-sin(
)cos(
)=
-
-1-
×
=-
,
故答案为-
.
| 25π |
| 6 |
| 10π |
| 3 |
| 25π |
| 4 |
| 7π |
| 3 |
| 13π |
| 6 |
| π |
| 6 |
| 4π |
| 3 |
| π |
| 4 |
| π |
| 3 |
| π |
| 6 |
=sin
| π |
| 6 |
| π |
| 3 |
| π |
| 4 |
| π |
| 3 |
| π |
| 6 |
| 1 |
| 2 |
| 1 |
| 2 |
| ||
| 2 |
| ||
| 2 |
| 7 |
| 4 |
故答案为-
| 7 |
| 4 |
点评:本题主要考查利用诱导公式进行化简求值,属于基础题.
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