题目内容
若数列{an}、{bn}中,a1=3,b1=0,当n≥2时,an=解析:
an+bn=
[(2an-1+bn-1)+(an-1+26n-1)]=an-1+bn-1=an-2+bn-2=…=a1+b1=0+3=3,
数列{an+bn}为常数数列,Sn= n(a1+b1)=3n.
练习册系列答案
相关题目
题目内容
若数列{an}、{bn}中,a1=3,b1=0,当n≥2时,an=解析:
an+bn=
[(2an-1+bn-1)+(an-1+26n-1)]=an-1+bn-1=an-2+bn-2=…=a1+b1=0+3=3,
数列{an+bn}为常数数列,Sn= n(a1+b1)=3n.