题目内容
已知函数f(x)=
+
+
+
,则f(-
+
)+f(-
-
)=______.
| x |
| x+1 |
| x+1 |
| x+2 |
| x+2 |
| x+3 |
| x+3 |
| x+4 |
| 5 |
| 2 |
| 2 |
| 5 |
| 2 |
| 2 |
∵f(x)=
+
+
+
,
∴f(-5-x)=
+
+
+
=
+
+
+
,
∴f(x)+f(-5-x)=[(
+
)+(
+
)+(
+
)+(
+
)]=8.
∵-
+
+(-
-
)=-5,
∴f(-
+
)+f(-
-
)=8.
故答案为:8.
| x |
| x+1 |
| x+1 |
| x+2 |
| x+2 |
| x+3 |
| x+3 |
| x+4 |
∴f(-5-x)=
| -5-x |
| -4-x |
| -4-x |
| -3-x |
| -3-x |
| -2-x |
| -2-x |
| -1-x |
=
| x+5 |
| x+4 |
| x+4 |
| x+3 |
| x+3 |
| x+2 |
| x+2 |
| x+1 |
∴f(x)+f(-5-x)=[(
| x |
| x+1 |
| x+2 |
| x+1 |
| x+1 |
| x+2 |
| x+3 |
| x+2 |
| x+2 |
| x+3 |
| x+4 |
| x+3 |
| x+3 |
| x+4 |
| x+5 |
| x+4 |
∵-
| 5 |
| 2 |
| 2 |
| 5 |
| 2 |
| 2 |
∴f(-
| 5 |
| 2 |
| 2 |
| 5 |
| 2 |
| 2 |
故答案为:8.
练习册系列答案
相关题目