题目内容
若|
|=|
|=|
-
|则
与
+
的夹角为( )
| a |
| b |
| a |
| b |
| b |
| a |
| b |
| A.30° | B.60° | C.150° | D.120° |
设|
|=|
|=|
-
|=t
∴|
-
|2=
2+
2-2
=t2
∴2
=t2
∵(
+
) 2=
2+
2+2
=3t2
∴
|+
| =
t
∴cos<
,
+
>=
=
∴
与
+
的夹角为:30°
故选A
| a |
| b |
| a |
| b |
∴|
| a |
| b |
| a |
| b |
| a |
| b |
∴2
| a |
| b |
∵(
| a |
| b |
| a |
| b |
| a |
| b |
∴
| a |
| b |
| 3 |
∴cos<
| b |
| a |
| b |
| ||||||
|
|
| ||
| 2 |
∴
| b |
| a |
| b |
故选A
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