题目内容
已知a>0,过M(a,0)任作一条直线交抛物线y2=2px(p>0)于P,Q两点,若
+
为定值,则a=( )
| 1 |
| |MP|2 |
| 1 |
| |MQ|2 |
A.
| B.2p | C.
| D.p |
设直线PQ的参数方程为x=a+tcosα,y=tsinα
则P,Q点的坐标分别为:(a+t1cosα,t1sinα),(a+t2cosα,t2sinα),
∴|MP|2=(a+t1cosα-a)2+(t1sinα)2=t12cos2α+t12sin2α=t12
|MQ|2=(a+t2cosα-a)2+(t2sinα)2=t22cos2α+t22sin2α=t22
又∵P,Q在抛物线y2=2px,
∴(t1sinα)2=2p(a+t1cosα)
(t2sinα)2=2p(a+t2cosα)
∴sin2αt12-2pcosαt1-2pa=0
sin2αt22-2pcosαt2-2pa=0
∴t1,t2是方程sin2αt2-2pcosαt-2pa=0的两根,
∴t1+t2=
,t1•t2=-
t12+t22=(t1+t2)2-2t1t2=
∵
+
=
+
=
=
=
为定植,∴a=p
故选D
则P,Q点的坐标分别为:(a+t1cosα,t1sinα),(a+t2cosα,t2sinα),
∴|MP|2=(a+t1cosα-a)2+(t1sinα)2=t12cos2α+t12sin2α=t12
|MQ|2=(a+t2cosα-a)2+(t2sinα)2=t22cos2α+t22sin2α=t22
又∵P,Q在抛物线y2=2px,
∴(t1sinα)2=2p(a+t1cosα)
(t2sinα)2=2p(a+t2cosα)
∴sin2αt12-2pcosαt1-2pa=0
sin2αt22-2pcosαt2-2pa=0
∴t1,t2是方程sin2αt2-2pcosαt-2pa=0的两根,
∴t1+t2=
| 2pcosα |
| sin2α |
| 2pa |
| sin2α |
t12+t22=(t1+t2)2-2t1t2=
| 4(p2cos2α +pasin2α) |
| sin4α |
∵
| 1 |
| |MP|2 |
| 1 |
| |MQ|2 |
| 1 |
| t12 |
| 1 |
| t22 |
| t1+t2 |
| (t1•t2)2 |
=
| ||
(
|
| pcos2α+asin2α |
| pa2 |
故选D
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