题目内容
已知
=a,则a2-c2的值为
| lim |
| x→2 |
| x2+cx+2 |
| x-2 |
-8
-8
.分析:由
=a,知4+2c+2=0,解得c=-3.故a=
=
=1,由此能求出答案.
| lim |
| x→2 |
| x2+cx+2 |
| x-2 |
| lim |
| x→2 |
| x 2-3x+2 |
| x-2 |
| lim |
| x→2 |
| (x-2)(x-1) |
| x-2 |
解答:解:∵
=a,
∴4+2c+2=0,
解得c=-3.
∴
=a
=
=
=
(x-1)
=1.
∴a2-c2=1-9=-8.
故答案为:-8.
| lim |
| x→2 |
| x2+cx+2 |
| x-2 |
∴4+2c+2=0,
解得c=-3.
∴
| lim |
| x→2 |
| x2+cx+2 |
| x-2 |
=
| lim |
| x→2 |
| x 2-3x+2 |
| x-2 |
| lim |
| x→2 |
| (x-2)(x-1) |
| x-2 |
=
| lim |
| x→2 |
=1.
∴a2-c2=1-9=-8.
故答案为:-8.
点评:本题考查极限的运算,解题时要认真审题,仔细解答,注意极限逆运算的灵活运用.
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