题目内容
设2a=5b=t,且
=3,则t=______.
| a+b |
| ab |
∵2a=5b=t,
∴a=log2t,b=log5t,
∴
=
=
+
=logt2+logt5
=logt10=3,
∴t3=10,
∴t=
.
故答案为:
.
∴a=log2t,b=log5t,
∴
| a+b |
| ab |
| log2t+log5t |
| log2t•log5t |
=
| 1 |
| log2t |
| 1 |
| log5t |
=logt2+logt5
=logt10=3,
∴t3=10,
∴t=
| 3 | 10 |
故答案为:
| 3 | 10 |
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