题目内容
化简
-10lg1-log5
+(
)-
=
| |||||
|
| |||
| 5 |
|
| 2 |
| 3 |
a+1
a+1
．分析：利用有理数指数幂的运算性质和运算法则，把
-10lg1-log5
+(
)-
等价转化为a
+
-
-0-log55-
+[(
)
]-
，由此能求出结果．
| |||||
|
| |||
| 5 |
|
| 2 |
| 3 |
| 1 |
| 2 |
| 5 |
| 4 |
| 3 |
| 4 |
| 1 |
| 3 |
| 27 |
| 8 |
| 1 |
| 2 |
| 2 |
| 3 |
解答：解：
-10lg1-log5
+(
)-
=a
+
-
-0-log55-
+[(
)
]-
=a+
+(
)3×
=a+1．
故答案为：a+1．
| |||||
|
| |||
| 5 |
|
| 2 |
| 3 |
=a
| 1 |
| 2 |
| 5 |
| 4 |
| 3 |
| 4 |
| 1 |
| 3 |
| 27 |
| 8 |
| 1 |
| 2 |
| 2 |
| 3 |
=a+
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
=a+1．
故答案为：a+1．
点评：本题考查有理数指数幂的运算性质和运算法则，是基础题．解题时要认真审题，仔细解答．
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