题目内容
已知向量
,
,
满足
|=1,|
|=2,
=
+
,
⊥
,则
与
的夹角等于( )
| a |
| b |
| c |
| |a |
| b |
| c |
| a |
| b |
| c |
| a |
| a |
| b |
| A.30° | B.60° | C.120° | D.90° |
设
与
的夹角等于α
∵向量
,
,
满足
|=1,|
|=2,
=
+
,
⊥
,
∴(
+
)•
=
2+
•
=1+2×1×cosα=0
∴cosα=-
∵α∈[0,π]
∴α=120°
故选C.
| a |
| b |
∵向量
| a |
| b |
| c |
| |a |
| b |
| c |
| a |
| b |
| c |
| a |
∴(
| a |
| b |
| a |
| a |
| b |
| a |
∴cosα=-
| 1 |
| 2 |
∵α∈[0,π]
∴α=120°
故选C.
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