Question

集合M={a+3+(b²-1)i,8},集合N={3i,(a²-1)+(b+2)i}同时满足M∩NM,M∩N≠,求整数a、b.

Answer 1

解：依题意得

(a+3)+(b²-1)i=3i                               ①

    或8=(a²-1)+(b+2)i.                         ②

    由①得a=-3,b=±2.

    经检验a=-3,b=-2不合题意,舍去.

∴a=-3,b=2.

    由②得a=±3,b=-2.

    又a=-3,b=-2不合题意,舍去.

∴a=-3,b=-2.

    综合①②得a=-3,b=2或a=3,b=-2.