题目内容
若向量
,
满足|
|=|
|=2,
与
的夹角为60°,则|
+
|=( )
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| b |
A.2
| B.2
| C.4 | D.12 |
∵
=
=2,夹角为60°,
∴
•
=
•
cos60°=2,
∴|
+
|2=
2+2
•
+
2=4+4+4=12,可得|
+
|=2
故选B
| |a| |
| |b| |
∴
| a |
| b |
| |a| |
| |b| |
∴|
| a |
| b |
| a |
| a |
| b |
| b |
| a |
| b |
| 3 |
故选B
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