题目内容
数列{an},an=
(n∈N+),且数列{an}的前n项和为sn=9,则n的值为( )
| 1 | ||||
|
| A.98 | B.99 | C.100 | D.101 |
因为an=
=
-
,
所以sn=a1+a2+…+an
=
-1+
-
+…+
-
=
-1.
∵Sn=9,∴
-1=9,
∴n=99.
故选B.
| 1 | ||||
|
| n+1 |
| n |
所以sn=a1+a2+…+an
=
| 2 |
| 3 |
| 2 |
| n+1 |
| n |
=
| n+1 |
∵Sn=9,∴
| n+1 |
∴n=99.
故选B.
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