题目内容
若
=(1,2),
=(x,1),
=
+2
,
=2
-
,且
⊥
,则x=( )
| a |
| b |
| m |
| a |
| b |
| n |
| a |
| b |
| m |
| n |
| A.2 | B.
| C.
| D.-2或
|
∵
=(1,2),
=(x,1),
∴
=
+2
=(1+2x,4)
=2
-
=(2-x,3)
又∵
⊥
,
∴
•
=(1+2x)•(2-x)+3×4=0
即-2x2+3x+14=0
解得x=-2或x=
故选D
| a |
| b |
∴
| m |
| a |
| b |
| n |
| a |
| b |
又∵
| m |
| n |
∴
| m |
| n |
即-2x2+3x+14=0
解得x=-2或x=
| 7 |
| 2 |
故选D
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