题目内容
设数列{an}和{bn}都是等差数列,其中a1=25,b1=75,且a100+b100=100,则数列{an+bn}的前100项之和是( )?
| A.1000 | B.10000 | C.1100 | D.11000? |
∵{an}、{bn}都是等差数列,
∴{an+bn}是等差数列,
∵a1=25,b1=75,a100+b100=100,
∴a1+b1+a100+b100=200,
∴S100=
=10000
故选B
∴{an+bn}是等差数列,
∵a1=25,b1=75,a100+b100=100,
∴a1+b1+a100+b100=200,
∴S100=
| 100(a1+b1+a100+b100) |
| 2 |
故选B
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