题目内容
若向量
,
满足|
|=1,|
|=
,且(
+
)⊥(2
-
)=0,则
,
的夹角为( )
| a |
| b |
| a |
| b |
| 2 |
| a |
| b |
| a |
| b |
| a |
| b |
| A.90° | B.120° | C.60° | D.45° |
∵(
+
)⊥(2
-
),∴(
+
)•(2
-
)=2
2+
•
-
2=2+
•
-2=
•
=0,
∴
⊥
,则a与b的夹角为90°,
故选 A.
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| a |
| b |
| b |
| a |
| b |
| a |
| b |
∴
| a |
| b |
故选 A.
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