题目内容
等比数列{an}中,an>0且a5a6=81,则log3a1+log3a2+…+log3a10的值是( )
| A.20 | B.10 | C.5 | D.40 |
由题意,log3a1+log3a2+…+log3a10=log3(a1a2…a10)=log3(a1a2…a10)=5log3(a5a6)
∵a5a6=81
∴log3a1+log3a2+…+log3a10=5log3(81)=5log3(34)=20
故选A.
∵a5a6=81
∴log3a1+log3a2+…+log3a10=5log3(81)=5log3(34)=20
故选A.
练习册系列答案
相关题目